Ответ: [tex] \frac{7p^4}{10q^3} * \frac{5q}{14p^2} : \frac{3p}{4q^4} =
= \frac{7p^4* 5q*4q^4}{10q^3*14p^2*3p}= \frac{140*p^4q}{140*3 *p^3q^3 } = \frac{p}{3q^2} [/tex]