Ответ: [tex]\bf u_0=0\\
u=72 \frac{_K_M}{4}=20 \frac{_M}{c} \\
m=8_T=8000_K_\Gamma\\
——\\
\Delta p-?[/tex][tex]\bf\Delta p=Ft=mat= \frac{m(u-u_0)t}{t}=mu\\
\Delta p=8000*20=160000 \frac{_K_\Gamma*_M}{_C} =160 \frac{_T*_M}{_C} [/tex]