Ответ: 2Al+3H2SO4=Al2(SO4)3+3H2m(H2SO4)=200*0.049=9.8гn(H2SO4)=9.8/98=0.1мольn(H2)=0.1*3/3=0,1мольV(H2)=0.1*22.4=2.24л