Ответ:
[tex](x+\frac{1}{3})(\frac{1}{9}-\frac{1}{3}x+x^2) =\frac{1}{9}x-\frac{1}{3}x^2+x^3+\frac{1}{27}-\frac{1}{9}x+\frac{1}{3}x^2=x^3+\frac{1}{27}[/tex]
Ответ:
[tex](x+\frac{1}{3})(\frac{1}{9}-\frac{1}{3}x+x^2) =\frac{1}{9}x-\frac{1}{3}x^2+x^3+\frac{1}{27}-\frac{1}{9}x+\frac{1}{3}x^2=x^3+\frac{1}{27}[/tex]