Ответ: 1)a/3(a-3)-3/a(a+3)-(a²+9)/3(a-3)(a+3)==(a³+3a²-9a+27-a³-9a)/3a(a-3)(a=3)=(3a²-18a+27)/3a(a-3)(a+3)==3(a²-6a+9)/3a(a-3)(a+3)=3(a-3)²/3a(a-3)(a+3)=(a-3)/a(a+3)2)(a-3)/4(a+3)²:(a-3)/a(a+3)=(a-3)/4(a=3)²*a(a+3)/(a-3)=a/4(a+3)

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