Ответ: Решение:1) y\’ = (x tgx)\’ = x\’ * tgx + (tgx )\’ * x = 1 * tgx + (1/cos^2x) * x = tgx + (x/cos^2x).2) y\’ = (sinx tgx)\’ = sinx\’ * tgx + (tgx )\’ * sinx = cosx * tgx + (1/cos^2x) * sinx = cosx * (sinx / cosx) + (sinx/cos^2x) = sinx + (sinx/cos^2x).3) y\’ = (x ctgx)\’ = x\’ * ctgx + (ctgx )\’ * x = 1 * ctgx — (1/sin^2x) * x = ctgx — (x/cos^2x).4) y\’ = (cosx ctgx)\’ = cosx\’ * ctgx + (ctgx )\’ * cosx = -sinx * ctgx — (1/sin^2x) * cosx = -sinx * (cosx / sinx) — (cosx/cos^2x) = -cosx — (cosx/sin^2x).